Aug 3, 2020 · Now lets do it using the geometric method that is repeated multiplication, in this case we start with x goes from 0 to 5 and our sequence goes like this: 1, 2, 2•2=4, 2•2•2=8, 2•2•2•2=16, …

Sep 20, 2021 · So for, the above formula, how did they get (n + 1) (n + 1) a for the geometric progression when r = 1 r = 1. I also am confused where the negative a comes from in the following …

For all questions that involve the geometric distribution in the context of probability, that is, the law of a random variable whose outcome is the number of attempts we need before a first success in …

3 A clever solution to find the expected value of a geometric r.v. is those employed in this video lecture of the MITx course "Introduction to Probability: Part 1 - The Fundamentals" (by the way, an extremely …

Dec 10, 2025 · None of the existing answers mention hard limitations of geometric constructions. Compass-and-straightedge constructions can only construct lengths that can be obtained from given …

May 26, 2015 · I'm not familiar with the equation input method, so I handwrite the proof. I'm using the variant of geometric distribution the same as @ndrizza. Therefore E [X]=1/p in this case. handwritten …

Apr 1, 2016 · What is the "definitive" definition of a geometric series? I phrased the question this way, because I've checked multiple Calculus textbooks, as well as Paul's Online Math Notes, and they …

May 23, 2014 · 21 It might help to think of multiplication of real numbers in a more geometric fashion. 2 2 times 3 3 is the length of the interval you get starting with an interval of length 3 3 and then stretching …

Apr 10, 2020 · Geometric Series in Sigma Notation with natural log Ask Question Asked 5 years, 9 months ago Modified 5 years, 9 months ago

Jul 2, 2019 · Probabilities of random geometric objects having certain properties (enclosing the origin, having an acute angle,...); expected counts, areas, ... of random geometric objects. For questions …